Rainbow-electronics MAX5098A Manual de usuario Pagina 23

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MAX5098A
Dual, 2.2MHz, Automotive Buck or Boost
Converter with 80V Load-Dump Protection
______________________________________________________________________________________ 23
3) Place a zero
where
and R
F
10kΩ.
4) Calculate C
I
for a target unity crossover frequency, f
C
.
5) Place a pole
or 5 x f
C
, whichever
is lower,
6) Place a second zero, f
Z2
, at 0.2 x f
C
or at f
LC
,
whichever is lower.
7) Place a second pole at 1/2 the switching frequency.
Boost Converter Compensation
The boost converter compensation gets complicated
due to the presence of a right-half-plane zero
f
ZERO,RHP
. The right-half-plane zero causes a drop in
phase while adding positive (+1) slope to the gain
curve. It is important to drop the gain significantly below
unity before the RHP frequency. Use the following pro-
cedure to calculate the compensation components:
1) Calculate the LC double-pole frequency, f
LC
, and
the right-half-plane-zero frequency.
where
D
V
V
R
V
I
IN
OUT
MIN
OUT
OUT MAX
=
=
()
1
()
f
DR
L
ZERO RHP
MIN
OUT
,
=
()
×
()
1
2
2
π
f
D
LC
LC
OUT OUT
=
××
1
2π
C
C
fRC
CF
F
SW F F
=
×× ××
()
205 1π .
R
fC
R
ZI
I
1
1
2
2
=
××
π
R
fC
I
PI
=
××
1
2
1
π
C
fL C V
VR
I
C OUT OUT OSC
IN F
=
×× × ×
×
2π
C
fR
F
LC F
=
×××
1
2075π .
f
RC
at f
Z
FF
LC1
1
2
075=
××
×
π
..
R1
R
F
COMP_
V
OUT
V
REF
R2
R
I
C
I
C
F
C
CF
-
+
g
M
FB_
Figure 5. Type III Compensation Network
PGND_
DRAIN_
MAX5098A
V
L
VDRV
V+
V
OUT_
BST_/VDD_
C
OUT
SGND
PGND_
DRAIN_
SOURCE_
SOURCE_
FB_
Figure 6. Boost Application
f
RC
at f
P
II
ZERO ESR1
1
2
=
××π
,
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